Question
Sheetal rides a bike at an average speed of 40 kmph and
reaches her destination in 5 hours. Hemlata covers the same distance in 4 hrs. If Sheetal increases her average speed by 10 kmph and Hemlata increases her average speed by 10 kmph, what would be the difference in their time taken to reach destination?Solution
Sheetalâs speed= 40 km/hr. Time taken by Sheetal = 5 hrs. Distance = Speed Ă Â Time = 40 Ă 5 = 200 km. â´ Distance covered by Hemlata  = 200  km. Time taken by Hemalata = 4 hrs. â´ Hemlataâs Speed = (Distance )/Time = (200 )/4 = 50 km/hr. Sheetalâs increased speed= 50 km/hr. â´ Time taken by Sheetal = (200 )/50 = 4 hrs.  Hemlataâs increased speed = 60 km/hr. â´ Time taken by Hemlata = (200 )/60 = 31/3 hrs. = 3hrs 20 minutes. â´ Required difference = 4 hrs â 3hrs 20 minutes = 40 minutes.
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