Question
Train βAβ running with a speed of 54 km/hr can cross
a standing goods train of 4 times its length in 30 seconds. Find the time taken by 310 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 20 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 54 Γ (5/18) = 15 m/s According to the question, 4x + x = 15 Γ 30 => 5x = 450 => x = 90 Therefore, time taken by train βBβ to cross train βAβ = {(90 + 310)/(30 + 20)} = 8 seconds
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