A boy goes to his school at 1/6th of the speed at which he returns from his school. Average speed during the whole trip (i.e. one round) is 24 km/h. What is the speed of the boy while he was going to his school?
Speed while going to school = x/6 Speed while returning = x Average speed = (2 × S1 × S2)/(S1 + S2) => 24 = (2 × x/6 × x)/(x/6 + x) => x = 84 Speed while going to school = 84/6 = 14 km/hr
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