Start learning 50% faster. Sign in now
Let the usual speed be x km/hr New speed = 125% of x = 5x/4 km/hr Distance = 495 km According to the question 495/x – 495/(5x/4) = 90/60 495 x [(5 – 4)/5x] = 3/2 Therefore, x = 495 x (1/5) x (2/3) = 66 km/hr
I. 8x – 3y = 85
II. 4x – 5y = 67
I. x² - (16)2 = 0
II. 2y - 14 = 0
I.70x² - 143x + 72 = 0
II. 80 y² - 142y + 63 = 0
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. 7p + 8q = 80
II. 9p – 5q = 57
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 27x² - 114x + 99 = 0
Equation 2: 18y² - 70y + 68 = 0
I. x2 - 4x – 21 = 0
II. y2 + 12y + 20 = 0
I. 6x2- 41x+13=0
II. 2y2- 19y+42=0
I. 144x² - 163x - 65 = 0
II. 91y² - 128y -48 = 0
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0