Question
If a person walks 25% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 495 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 125% of x = 5x/4 km/hr Distance = 495 km According to the question 495/x – 495/(5x/4) = 90/60 495 x [(5 – 4)/5x] = 3/2 Therefore, x = 495 x (1/5) x (2/3) = 66 km/hr
It is plan of activities to be undertakon in a particular time sequence.
Which among the following market structures has the highest product differentiation?
Who is known as the father of 'university extension?
The main reason behind formation of a covalent bond is-
In-house procedures for continuous monitoring of operations and systematic day-to-day checking of produced data for reliability in the Analysis Laborat...
Microorganism involve in conversion from nitrite to nitrate
The haploid chromosome complement of a species is represented by
Transfer cells are highly specialized plant cells which are involved inÂ
A combination of erosion permitting and resistive crops in alternate rows are constructed perpendicular to the direction of wind and water flow, to pre...
Which of the following is a short-day plant?
Relevant for Exams:
