Question
If a person walks 20% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 459 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 120% of x = 6x/5 km/hr Distance = 459 km According to the question 459/x – 459/(6x/5) = 90/60 459 x [(6 – 5)/6x] = 3/2 Therefore, x = 459 x (1/6) x (2/3) = 51 km/hr
- In triangle DEF, GH is drawn parallel to side EF. If DG = 9 cm, GE = 3 cm and DH = 6 cm, find DF.
What is the height of an equilateral triangle with a side length of 12√5 cm?
In a ∆ABC, points P, Q and R are taken on AB, BC and CA, respectively, such that BQ = PQ and QC = QR. If ∠ BAC = 75°, what is the measure of &...
Two triangles DEF and XYZ are congruent to each other such that DE = 10 cm, YZ = 24 cm, and ∠DEF = ∠XYZ = 90⁰. Find the circumradius of ΔDEF.
...The sides of a triangle are 13 cm, 14 cm, and 15 cm. What is the area of the triangle?
- The base of a right pyramid is an equilateral triangle with side 10 cm. If the height of the pyramid is 55√3 cm, calculate the volume of the pyramid.
If two triangles EFG and UVW are congruent, then which of the following statement(s) is/are true?
I. EF = UV
II. ∠FEG = ∠UVW
Find the inradius of an equilateral triangle whose altitude is 9√3 cm.
In a right-angled triangle, the legs are in the ratio 3:4, and the hypotenuse is 25 cm. Find the perimeter of the triangle.
If the angles of a triangle are in the ratio of 2:5:8, then find the value of the biggest angle.
Relevant for Exams:
