Question
If a person walks 25% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 247.5 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 125% of x = 5x/4 km/hr Distance = 247.5 km According to the question 247.5/x – 247.5/(5x/4) = 90/60 247.5 x [(5 – 4)/5x] = 3/2 Therefore, x = 247.5 x (1/5) x (2/3) = 33 km/hr
More Time and distance Questions
What will come in the place of question mark (?) in the given expression?
(12.09)2 × 5.98 ÷ 26.95 = ? + 25Â
√441 * 7 – 10% of 250 + ? = 140% of 120
30% of 8/5 × 5/7 × 2870 =?
1231 + 1312 + 2113 – 3211 = ?
{(3/8) + (5/6)} × 120 – 53 = ?Â
What will come in the place of question mark (?) in the given expression?
23 X 35 - ? = (132 + 16) X 3 + 25
56 × 18 + ? × 21 – 49 × 12 = 63 × 26Â
- Evaluate: 168 ÷ 12 × 5 + 190 – 20% of 450
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