A train covers a certain distance at a speed of 24 km/h and the next same distance with a speed of 30 km/h and the next same distance with a speed of 40 km/h. find the average speed?
Since the distance is same in all the conditions. Therefore, Average speed = 3xyz/(xy + yz + zx) Average speed = 3 x 24 x 30 x 40/(24 x 30 + 30 x 40 + 40 x 24) Average speed = 3 x 24 x 30 x 40/(720 + 1200 + 960) = 86400/2880 = 30 km/hr
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