Question
A train covers a distance of 60 km at the speed of 30
km/h the next 130 km distance covers with a speed of 50 km/h and last 56 km with the speed of 40 km/h find the average speed of the train?Solution
Since the train covers different distance with different speeds. So, Average speed = Total Distance/Total Time Total distance = 60 + 130 + 56 = 246 km Time1 = 60/30, Time2 = 130/50 & Time3 = 56/40 Total Time = 60/30 + 130/50 + 56/40 Therefore, Average Speed = 246/(60/30 + 130/50 + 56/40) = 41 km/hr
(p + 3) 2 + (q – 7) 2 + (r + 4)2 = 0, then find the value of p + q – r.
√(92×8 ×52+700) = ?
(x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then find the value of 4x - 3y + z.
What will come in the place of question mark (?) in the given expression?
?2 = (392 × 224) ÷ (112 × 28) + 62
If 5x - 13xy + 6y = 0, find x : y.
  = ?If x = 35, then the value of x5 - 36x4 + 36x3 - 36x2 + 36x - 1 is
If x + y + z = 30, x² + Y² + z² = 460 and x z = y², then find the value of x z?
If ( m+n ) : √ (mn) = 4, m>n , Then find the value of m : n ?
If √k + (1/√k) = 8, then find the value of k + (1/k).
