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Let the initial distance between A and B be 'D' km. A's speed = 25 km/hr, B's speed = 15 km/hr. Time to meet = t hours. A covers 25t km, B covers 15t km. Given 25t=15t+20 (distance by A is 20 km more than B). Solve: 
Initial distance = D = 25t+15t = 40t. Substitute t = 2: D = 40(2) = 80km.
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
Find the simplified value of the given expression.
{12.75 × √64 + 13.5 × √(√256)} ÷ 6 + 49.5 ÷ 5.5
(√7225 x √1225)/(√625) = ?
The value of {5 − 5 ÷ (10 − 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
390/? = √256 + 3.5
Find the simplified value of the given expression:
224 ÷ 4 + 7 X 36 - 8 of 15 + 162 - 300
2/5 of 3/4 of 7/9 of 7200 = ?
√? + √1296 + √729 = 464/4
