Question
βAβ and βBβ started moving towards each other at
same time with a speed of 27 km/hr and 15 km/hr, respectively. If the distance covered by βAβ is 36 km more than that by βBβ, when they meet then find the initial distance between them.Solution
Difference in speed = 27 - 15 = 12 km/hr Time taken = 36/12 = 3hrs Required distance = travelled distance by A + travelled distance by B = 27 Γ 3 + 15 Γ 3 = 81 + 45 = 126 km
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