A train has to cover a distance of 90 km in 15 hours. If it covers half the journey in 4/5th of the time, the speed to cover remaining distance in the time left has to be?
Total Distance = 90 km Total Time = 15 hours 4/5th of the time = 15 × 4/5 = 12 hours Now, remaining distance = 90 - 45 = 45km Remaining time = 15 – 12 = 3 hours Average speed to cover the distance of 45 km will be 45/3 = 15km/hr.
Two numbers are less than a third number by 40% and 46% respectively. Find the percent by which the second number is less than the first.
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