A train has to cover a distance of 90 km in 15 hours. If it covers half the journey in 4/5 th of the time, the speed to cover remaining distance in the time left has to be
Total Distance = 90km Total Time = 15 hours 4/5th of the time = 15 × 4/5 = 12 hours Now, remaining distance = 90-45 = 45km Remaining time = 15 – 12 = 3 hours Average speed to cover the distance of 45 km will be 45/3 = 15km/hr.
In the given figure, B and C are the centres of the two circles. ADE is the common tangent to the two circles. If the ratio of the radius of both the ci...
In the given figure, radius of a circle is 14 √2 cm. PQRS is a square. EFGH, ABCD, WXYZ and LMNO are four identical squares. What is the total area (i...
In ABC,D is a point on side AB such that BD = 2 cm and DA = 3 cm. (E is a point on BC such that DE) AC, and AC = 4 cm. Then (Area of A BDE) : (Area of ...
In the given figure, ABC is a right angled triangle. ∠ ABC = 90 0and ∠ ACB = 60 0. If the radius of the smaller circle is 2 cm...
The length of a tangent from a point A at a distance 5 cms. from the centre of the circle is 4 cms. Radius of the circle is
B1 is a point on the side AC of ∆ ABC and B1B is joined. line is drawn through A parallel to B1B meeting BC at A1 and another line is drawn through C ...
PQRS is a cyclic quadrilateral of which PQ is the diameter. Diagonals PR and QS intersect at A. If SQR = 25°, then angle PAS measures
If median AD of an equilateral ∆ABC is 6 cm and G is centroid. Find AG?
In triangle ABC, angle A is 90 ...