Given, speed of train B = 100 km/ph Let speed of train C = x km/ph length of train B = 150 m = 0.15 km length of train C = 250 m = 0.25 km time taken = 2 minutes = 2/60 = 1/30 time taken = (length train A + length train B)/( difference i n speed) = 0.4 / (100−x) 1/30 = 0.4 / (100−x) 100 − x = 0.4 × 30 100 − 12 = x X (speed of the train C) = 88 km/ph
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Profit percentage received on a product when sold for Rs.480 is equal to the percentage loss incurred when the same product is sold for Rs.300. Find the...
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Cost price of a bag is Rs.600. The shopkeeper marked it 60% above the cost price and sold it after giving a discount of 20%. If the shopkeeper had sold ...
A shopkeeper sells an article for ₹18,500 at a loss of 20%. What was the cost price of the article?
