Question
If a car runs at 36 km/hr, it reaches its destination
late by 15 minutes but if runs at 45 km/hr it is late by 9 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [15 – 9]/60 x {(45 x 36)/[45 – 36]} => (6/60) x (45 x 36)/9 => 18 km Time, T = D/S (take any one of the speed) => 18/36 = 18/36 x 60 = 30 minutes Then, correct time is 30 – 15 = 15 minutes
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