Question
Buses A and B are moving around a circular ground of
radius 420 m. If the speeds of the buses A and B are 12 m/sec and 15 m/sec respectively, then what is the difference between the time taken by bus A and B to complete 3 round of the ground?Solution
Circumference if the ground = 2πr = 2 × 22/7 × 420 = 2640 m So, distance = 2640 m Time taken by bus A to cover 3 rounds of a ground = (2640/12) × 3 = 660 Time taken by bus B to cover 3 rounds of a ground = (2640/15) × 3 = 528 Required difference = 660 – 528 = 132
√10404 + √9604 - ∛1728 - ∛42875 = ?
1299.999 ÷ 325.018 × 24.996 = ?
24% of 400 × 16% of ? = 384
Determine the simplified value of the given mathematical expression.
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?Â
82% of 400 + √(?) = 130% of 600 - 85% of 400
192.251 + 326.233 + 125.021 + 19.273 = ?
45% of 360 - 160 + ? = √324
(160 × 12 - 13 × 20)/(120 × 2 + 2 × 35 + 2 × 11) = ?