Let the speeds of Ajay and Vishal be 3x and 2x km/hr respectively. Distance covered by Vishal in 72 seconds = 2x x (5/18) x 72 = 40x m Distance covered by Ajay in 42 seconds = 3x x (5/18) x 42 = 35x m According to the question, => 40x – 35x = 40 => x = 8 Therefore the speed of Vishal = 2x = 16 km/hr
?% of (112.31 ÷ 13.97 × 90.011) = 359.98
2.51% of 800 - 3.97% of 250 = ?
157.78% of 4820 + 92.33% of 2840 = ? + 115.55% of 1980
?% of 1200.22 + 319.82 = 3.99 × 295.64
[(5/9 of 719.87) + (59.73% of 450.31)] ÷ (√168.79 - 3/4 of 63.94) = ?
(15.98% of 399.99) - 6.998 = √?
4 √1295.98 × 1339.42 + ? = 73 × 26.01
(18.22) 2.02 + (13.89) 2.12 – (44.88) 2.07 = ? – 1604.85
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
