📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    Ajay and Vishal left the place ‘X’ with different

    speeds which are in the ratio 7:6 respectively. Ajay left the place 36 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 100 meters apart from Vishal, then find the speed of Vishal.(in km/hr)
    A 16 km/hr Correct Answer Incorrect Answer
    B 12 km/hr Correct Answer Incorrect Answer
    C 15 km/hr Correct Answer Incorrect Answer
    D 20 km/hr Correct Answer Incorrect Answer
    E 18 km/hr Correct Answer Incorrect Answer

    Solution

    Let Ajay’s speed = 7x, Vishal’s speed = 6x Vishal travels for 72 sec → Distance = 6x×72=432x Ajay starts 36 sec later, so he travels 36 sec → Distance = 7x×36=252x Gap between them = 432x−252x=180x=100 On solving we get 180x = 100 So, x = 5/9 Hence, Vishal speed = 6x  = 6 × (5/9) = 10/3 m/s Hence, To convert Vishal's speed from m/s to km/hr, use the conversion factor:

    1 m/s = 3.6 km/hr Given speed of Vishal: Vishal’s speed = 10/3 m/s Speed in km/hr = 10/3 × 3.6 = 36/3 = 12 km/hr

    Practice Next
    More Time and distance Questions

    Relevant for Exams:

    ask-question