A man travelled a distance of 47 km in 6 hours. He travelled panly on foot at a speed of 6(1/2) km/h and the rest on bicycle at a speed of 8(1/2)km/h. The distance travelled (in km) on bicycle is:
ATQ, Let the time he traveled on foot be Q hours. Distance traveled by bicycle = (6 - Q) hours According to the question, 6.5 × Q + 8.5 × (6 - Q) = 47 ⇒ Q = 2 Hence, the distance traveled on foot = 6.5 × 2 = 13 km
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