Solution

Since, the speed of the bike increases by 4 km/hr after every 1 hour, therefore the bike will travel 4 km extra after every 1 hour. Therefore, distance travelled by the bike in 1st hour = 30 km Distance travelled by the bike in 2nd hour = 30 + 4 = 34 km Distance travelled by the bike in 3rd hour = 34 + 4 = 38 km This form an AP i.e. 30, 34, 38………distance travelled in 10th hour Therefore, total distance travelled by the bike in 10 hours = sum of the AP Distance travelled in 10 hours = (n/2){2a + (n – 1)d} Where n = number of terms = 10, a = 1st term = 30 and d = common difference = 4 Therefore, distance travelled in 10 hours = (10/2){2 × 30 + (10 – 1) × 4} = (10/2)(60 + 36) = 480 km