Question
Average speed of βAβ during a 20-hour journey is 28
km/h. If he covered the first 240 km of his journey at a speed of 20 km/h, then find the speed at which βAβ travelled during the remaining journey.Solution
Total distance covered by βAβ = 20 Γ 28 = 560 km Time taken to cover 240 km = 240/20 = 12 hours Time taken to cover remaining distance = 20 β 12 = 8 hours So, required speed = {(560 β 240)/8} = 40 km/h
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