Question
Average speed of βAβ during a 20-hour journey is 30
km/h. If he covered the first 240 km of his journey at a speed of 20 km/h, then find the speed at which βAβ travelled during the remaining journey.Solution
Total distance covered by βAβ = 20 Γ 30 = 600 km Time taken to cover 240 km = 240/20 = 12 hours Time taken to cover remaining distance = 20 β 12 = 8 hours So, required speed = {(600 β 240)/8} = 45 km/h
- What will come in place of (?), in the given expression.
β2025 + 35% of 400 = ? 289 + 896 + 144 β 25% of 1100 =?
12.50% of 1440 - 17 × 51 + 721 =?
44.99% of 499.98 × (3.30/7.40)% of 1399.97 + 10.02 = ?
If x²y² + (1/ (x2y2)) = 83, then the value of xy – 1/xy is:
What will come in the place of question mark (?) in the given expression?
354 - 388 + 342 = ? - 84 Γ· 14 X β484
- What will come in place of (?), in the given expression.
(5Β³ + 3Β²) Γ 2 = ? - Simplify:

- What will come in place of the question mark (?) in the following questions?
100β[20+4Γ5]=?