Question
A man is travelling at a speed of 30 km/h such that he
will take 70 minutes to reach his destination. But after completing half the journey, the man took a break of 25 minutes and then continued his journey. Find the speed at which the man must cover rest of the journey to reach his destination in original time.Solution
Total distance to be covered = 30 × (70/60) = 35 km Time taken to cover half the distance at original speed = {(35 ÷ 2) ÷ 30} × 60 = 35 minutes Time remaining = 70 – 35 – 25 = 10 minutes Required speed = 17.5 ÷ 10 × 60 = 105 km/h
If x 8 + x -8 = 194, then find the value of (2x 2 – 4) 2 – 1.
(123×123×123 + 130×130×130)/(123×123 - 123×130 + 130×130) = ?
If p = 36 - q - r and pq + r(q + p) = 310, then find the value of (p² + q² + r²).
If
= 3 then If x² - 2x + 1 = 0, then find the value of (x + x⁻¹)².
If x4 + x3 + x2 + x + 1 = 0, then find the value of x1525 + x720 + 14 + x320 =?
If a 2 + b 2 = 89 and a 2 - b 2 = 39, then find the value of a 3 - b 3 - 3...
If √c + (1/√c) = 7, then find the value of c + (1/c).
`25(2/3)+11(1/9)+16(4/5)xx6(5/12)` = ? - `632/45`
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