Speed of a car and a bus is 30 km/h and 18 km/h, respectively. If the time taken by the car to cover a distance of ‘8x’ km is 1 hour less than time taken by the bus to cover a distance of ‘6x’ km, then find the value of ‘8x’.
According to the question, (6x/18) – (8x/30) = 1 Or, (6x × 5 – 8x × 3) ÷ 90 = 1 Or, (30x – 24x) ÷ 90 = 1 So, x = 15 Required value = 8 × 15 = 120
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