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According to the question, (6x/15) – (8x/25) = 1 Or, (6x × 5 – 8x × 3) ÷ 75 = 1 Or, (30x – 24x) ÷ 75 = 1 So, x = 12.5 Required value = 8 × 12.5 = 100
Find the largest three-digit number that leaves '3', '4' and '5' as remainder when it is divided by '7', '8' and '9', respectively.
Indicate the numbers that are divisible by both 2 and 3.
When N is divisible by 5 the remainder is 2. What is the remainder, when n³ is divided by 5?
Find the remainder when the number (289n + 147) is divided by 17.
4096 2048 514 64 4
...What is the smallest number that needs to be added to 978 to make it a multiple of 37?
Find the number of zeros at the end of 78!.
