Speed of a car and a bus is 18 km/h and 10 km/h, respectively. If the time taken by the car to cover a distance of ‘20x’ km is 1 hour less than time taken by the bus to cover a distance of ‘12x’ km, then find the value of ‘20x’
According to the question, (12x/10) – (20x/18) = 1 Or, (12x × 9 – 20x × 5) ÷ 90 = 1 Or, (108x – 100x) ÷ 90 = 1 So, x = 11.25 Required value = 20 × 11.25 = 225
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