X started to run from point ‘A’ to ‘B’ at a speed of 21 km/hr at 9:00 am and Y started to run from point ‘B’ to ‘A’ at a speed of 18 km/hr at 11:00 am. If they meet each other at 3:00 pm then find the distance between points ‘A’ and ‘B’.
Distance covered by X in 2 hours = 21 × 2 = 42 km Relative speed of X and Y = 21 + 18 = 39 km/hr Sum of distance covered by both in 4 hours = 39 × 4 = 156 km Total distance between points ‘A’ and ‘B’ = 42 + 156 = 198 km
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 8y2- 2y - 21 = 0
II. 2x2+ x - 6 = 0
I. 27(p + 2) = 2p(24 – p)
II. 2q2 – 25q + 78 = 0
I. 6p² + 17p + 12 = 0
II. 12q² - 25q + 7 = 0
I. 7x + 8y = 36
II. 3x + 4y = 14
I. 64x2 - 64x + 15 = 0
II. 21y2 - 13y + 2 =0
I. x² - 19x + 84 = 0
II. y² - 25y + 156 = 0
1.3wx = 40 – wy
2. b2 = 2b + p
3. d2 + d = q
Now, observe the given conditions:
One root of equation...
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0