1500 metres long train crosses a man who is moving in the same direction with a certain speed, in 50 seconds. If the same train can cross a tree in 15 seconds with the same speed, then find the speed of the man.
Speed of train = 1500/15 = 100 m/sec Let the speed of the man be ‘s’ m/sec Relative speed of the train = (100 – s) m/sec According to the question, (100 – s) = 1500/50 Or, s = 100 – 30 = 70 Therefore, speed of the man = 70 m/sec
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
766/51 ÷ 387/42 × 121/13 = ?
648.13 ÷ 35.86 + 28.88 × 13.13 – 39.92% of 900.19 = ?
1359.98 ÷ 20.48 × 12.12 = ? × 4.16
? (30.03 - 17.98 × 15.99 ÷ 12.01) = 729.03
124% of 620.99 + 11.65% of 1279.23 = ?
480.11 ÷ 15.98 × 5.14 – 134.9 = √?
Solve the following expression and calculate the approximate value.
802 of
{44.78% of (11.67 × 54.78)} ÷ 2.65 = ? + 19.25
3.55% of 8120 – 66.66% of 540 = ? – 28% of 5500
