1322 metres long train crosses a man who is moving in the same direction with a certain speed, in 40 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.
Speed of train = 1322/20 = 66.1 m/sec Let the speed of the man be ‘s’ m/sec Relative speed of the train = (66.1 – s) m/sec According to the question, (66.1 – s) = 1322/40 Or, s = 66.1 – 33.05 = 33.05 Therefore, speed of the man = 33.05 m/sec
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sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
...Simplifies-
(1 + tan²A) + (1+ 1 /tan²A)
[A] 1/ (sin²A-sin4 A)
[C] 1/ (cos2 A-sin4 A)
[B]...
Find the Value of Sin⁶`Theta` + Cos⁶`Theta` + 3Sin² `theta` Cos²`Theta`
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