Vikas covered a certain distance by bike. If he covers 40% of the distance at 40 km/h, 50% of the distance at 25 km/h and the remaining 10% distance at 10 km/h. Find his average speed over the whole distance.
ATQ, Let the total distance be 100x Now, Average speed = (100x)/[{(100x × 40%)/40}+{(100x × 50%)/25}+{(100x × 10%)/10}] = [100x/{(40x/40)+(50x/25)+(10x/10)}] = {100x/(x+2x+x)} = (100x/4x) = 25 km/h
(462.23 × 127.84 ÷ 153.88) ÷ √(31.98 × 7.92) = ? ÷ 15.15
180.25 × 14.995 ÷ √26 = ? × 5.985
(1280.23 ÷ 31.98) + (912.32 ÷ 23.9) + 1864.11 = ?
√ 27556.11 × √ 624.9 – (22.02) 2 =? × 5.95
`sqrt(1279.98+sqrt(243.97+sqrt(140.22+sqrt(6.875+sqrt(76.09+sqrt(24.97)))))) = ? `
(5.013 – 30.04) = ? + 11.98% of 4799.98
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
√323.89 × (3.20) ÷ 9.02 =?
416.021÷ 3.782 + 13.012× 24.987 =?
...