A cheetah can catch a deer running with a speed of 36 km/h and is 45 meters ahead of it, in 12 seconds. Find the time taken by the cheetah to catch a zebra that is 135 metres ahead of it and is running with a speed which is 70% of that of the deer.
Speed of the deer = 36 km/h = 36 × (5/18) = 10 m/s Distance covered by the cheetah in 12 seconds = 45 metres + distance covered by the deer in 12 seconds = 45 + 10 × 12 = 45 + 120 = 165 metres So, speed of the cheetah = 165/12 = 13.75 m/s Speed of the zebra = 10 × (70/100) = 7 m/s So, relative speed of the cheetah with respect to the zebra = 13.75 – 7 = 6.75 m/s Hence, time taken by the cheetah to catch the zebra = 135/6.75 = 20 seconds
32 of (16/8) of (30/24) of (120/x) = 30
5 × 14 + 100 ÷ 4 = 62 + ?
18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
What is the place value of 6 in 367892141?
32 + 26 × (484 ÷ 44) + 450 ÷ 9 = ?
132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
√(1889 – 125) + √(841 – 165) = ?
40% of 1820 + 80% of 630 = 90% of 1280 + ?
17% of 250 + ? = 108
Simplify-
x + 3(y + x – 2) – (x + y).