A and B are travelling towards each other with a speed of 20 km/hr and 30 km/hr. If they started at same time and A covered 18 km less distance than B before meeting him, then find the distance between them before starting.
Since, the time taken by A and B is same, therefore the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 20:30 = 2:3 Let the distance covered by A and B be 2x km and 3x km According to the question, 3x – 2x = 18 Or, x = 18 Therefore, distance between them before starting = 2x + 3x = 5x = 90 km
(1/8) × (256 × 2)/(8 × 4) + ?3 = 1730
√9604 + ∛205379 + 58% of 1500 = 520 + ?
672 ÷ 28 × 24 + 363 – 309 =?
10% of 80% of 50% of ? = 4
Solve.
15.73 +13.25 +16.73 – 28.71 = 5 ×?
√49 + √144% of 3600 = ?
32% of 4080 + 24% of 540 = ? % of 3200
(21 × 16 – 8) ÷ 41 = ?
862 - 37 – ? = – 432
84367 + 65441 + 32645 – 21145 – 10769 = ?
