A and B are travelling towards each other with a speed of 50 km/hr and 60 km/hr. If they started at same time and A covered 26 km less distance than B before meeting him, then find the distance between them before starting.
Since, the time taken by A and B is same, therefore the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 50:60 = 5:6 Let the distance covered by A and B be 5x km and 6x km According to the question, 6x – 5x = 26 Or, x = 26 Therefore, distance between them before starting = 6x + 5x = 11x = 286 km
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