Question
Average speed of βAβ during a 24-hour journey is 30
km/h. If he covered the first 140 km of his journey at a speed of 10 km/h, then find the speed at which βAβ travelled during the remaining journey.Solution
Total distance covered by βAβ = 24 Γ 30 = 720 km Time taken to cover 140 km = 140/10 = 14 hours Time taken to cover remaining distance = 24 β 14 = 10 hours So, required speed = {(720 β 140)/10} = 58 km/h
√10404 + √9604 - β1728 - β42875 = ?
1299.999 Γ· 325.018 Γ 24.996 = ?
24% of 400 × 16% of ? = 384
Determine the simplified value of the given mathematical expression.
What will come in the place of question mark (?) in the given expression?
(144 Γ 16 Γ· 12) Γ 6 = ?Β
82% of 400 + √(?) = 130% of 600 - 85% of 400
192.251 + 326.233 + 125.021 + 19.273 = ?
45% of 360 - 160 + ? = β324
(160 Γ 12 - 13 Γ 20)/(120 Γ 2 + 2 Γ 35 + 2 Γ 11) = ?