‘A’ and ‘B’ started moving towards each other at same time with a speed of 24 km/hr and 10 km/hr, respectively. If the distance covered by ‘A’ is 24 km more than that by ‘B’, then find the sum of distance covered by them.
Let the distance travelled by A be 'x' and that by B be 'x - 21'. Then, ATQ: => x/24 = (x - 24)/10 => 10x = 24x - 504 => 14x = 504 => x = 36 Distance covered by B = 36 - 21 = 15 Therefore, Required sum = 15 + 36 = 51 km.
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