A man walking at 4/5 of his regular speed, when a man covers a few distance in 3 hrs more than the time he takes to cover the same distance at his regular speed. Then what will be the time taken by him to cover the distance at his regular speed (in hrs) is?
ATQ, we can say that as we know that speed is inversely proportional to time so with 4/5 of usual speed he will take 5/4 of usual time. Now, (5/4) x usual time - usual time = 3 Usual time = (5−4)/4 = 3 Usual time = 3 x 4 = 12 hrs
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