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ATQ, Distance = 300km Relative speed = 25 + 35 = 60 kmph So, first time they meet after = (300/60) = 5 hours Now, in the second time both travelled (300 + 300) km distance and relative speed = 25 + 35 = 60 kmph They meet after (600/60) = 10 hours Similarly, for the third time, fourth time …8th time they meet after 10 hours in each case. Now, total time = (5 + 7) x 10 = 75 hours Required difference = (35 x 75) - (25 x 75) = 75(35 - 25) = 75 x 10 = 750km
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