ATQ, Let the efficiency of 'A' be 'a' units/day. So, total work = 16 × a = '16a' units So, work done by 'A' in 8 days = a × 8 = '8a'units So, work done by 'B' = 16a - 8a = '8a' units So, efficiency of 'B' = 8a ÷ (12 + 8) = '0.4a'units/day So, required time = 16a ÷ 0.4a = 40 days
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