We can say that the speed of cow is ‘a’ km/h Speed of dog = (a + 15) km/h According to question; 450/(a + 15) – 210/a = 3 150/(a + 15) – 70/a = 1 150x – 70(a + 15) = a(a + 15) 150a – 70a – 1050 = a2 + 15a a2 – 65a + 1050 = 0 Solving above equation we get a = 35, 30 So, speed of bus will be either 50 km/h or 45 km/h So distance cannot be determined
[{(1296 ÷ 18) ÷ 12} ÷ 6] + 82 + √625 = ?
2.4 of 7.2 of 1/57.6 of 4200 = ?
(0.064 × 3.2 × 2.5) ÷ (0.0016 × 4 × 1.25) = ?2 – 57
420 ÷ 7 + 140 % of 20 + ? × 13 = 18 × 15
(0.125)³÷ (0.25)² x (0.5)² = (0.5)?-3
Simplify the following expression
72 – 4(40 + 24 ÷ 6 × 6 – 4 × 4) + 40
236.23 - 653.23 + 696.23 = ?
[{(3 × 54 × 21)/63} + 6] / 6 = √?