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ATQ, Let the length of the Toll plaza be 't' metres Speed of Truck = 180 × 5/18 = 50 m/s According to the question, (200 + t)/50 = 10 Or, t = 300 metres Length of the second Truck = 300 – 180 = 120 metres Speed of the Truck = 252 × (5/18) = 70 m/s Therefore, (300 + 120)/70 = 6 seconds
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
1540 ÷ 7 - 184 ÷ 8 = ?
12.232 + 29.98% of 539.99 = ? × 5.99
√256 * 3 – 15% of 300 + ? = 150% of 160
18 × 15 + 86 – 58 =? + 38
[5 X {(52 X 5) - 10} + 50 of 20] = ?
4(1/3) × 2(11/14) = 50% of ? + 86/11
(15 x 6 + 60% of 500 - 16 x 7) = ?
25% of 140 + 2 × 8 = ? + 9 × 5
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶