Question
Amrita traveled a certain distance, covering 50% of it
at a speed of 15 km/h, then 40% of the remaining distance at 7.5 km/h, and the rest at 9 km/h. If it took her a total of 14 hours to complete the entire journey, what is the total distance she covered?Solution
ATQ, We can say that distance covered by Amrita be ‘100a’ km. Distance covered at 15 km/h = 100a × 0.50 = ‘50a’ km Distance covered at 7.5 km/h = 50a × 0.40 = ‘20a’ km Distance covered at 9 km/h = 50a – 20a = ‘30a’ km ATQ; (50a/15) + (20a/7.5) + (30a/9) = 14 Or, 150a + 120a + 150a = 14 × 45 Or, 420a = 14 × 45 So, a = 1.5 So, required distance = 100 × 1.50 = 150 km
- What will come in place of (?), in the given number series.
1, 4, 9, 16, ?, 36 - What will come in place of (?), in the given number series.
2, 5, 10, 17, ?, 37 10, 10, 15, 30, 75, ?
1236, 1445, 1675, 1933, 2226, ?
14, 17, 23, 32, ?, 59
13, 28, ?, 118, 238, 478
1221,     1100,     1000,     919,       ?
...16, 24, ?, 64, 104, 168, 272
14, 34, 19, 29, 24, ? , 29, 19
48, 95, 283, 1129, ?, 33841