Saket and Rakesh are brothers whose shops are located at a distance of 10km and 12km respectively from their home. Both of them start at the same time from home every day and reach their respective shops exactly at 8 am. When they decided to swap shops for a day, Saket started 4 minutes earlier than Rakesh. If both of them reached on time, what is the speed of Rakesh?
Since, ratio between distance covered by Saket and Rakesh = 10 : 12 = 5 : 6 ∴ Ratio between Speed of Saket and Rakesh = 5 : 6 Let speed of Saket and Rakesh be 5 x and 6 x respectively. ∴ 12/5x - 10/6x = 4/60⟹ (72-50 )/30x = 4/60 ⟹ 22/30x = 4/60⟹ 60 × 22 = 120 x ∴x = (60 × 22)/120 ∴ x = 11 ∴ Speed of Rakesh = 66 km/hr
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