Question
The two places are 60 km apart. A and B start walking
towards each other at the same time and meet each other after 6 hours. Had A traveled with 2/3rd of his speed and B traveled with a double of his speed, they would have met after 5 hours. The speed of A is:Solution
Let the speeds of βAβ and βBβ be βxβ km/h and βyβ km/h, respectively According to the question, (x + y) = (60/6) = 10 km/h Multiplying throughout by (2), we get (2x + 2y) = 20β¦β¦β¦. (I) Also, (2x/3) + 2y = 12 Or 2x + 6y = 36β¦β¦. (II) Subtracting equation (I) from equation (II), we get βyβ = 4 km /h putting the value of y in the equation (ii) x = 6km /h
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