Howrah Express is scheduled to reach Howrah at 8:00 am, but due to the high number of trains the train couldn't get clearance for platform, and it got stuck on the outer. The train’s average speed is 55km / hr., if it gets delayed by 30 min. It had a total of 23 stops in its journey at an average halt of 2 minutes. What percentage (approx.) more will be the average speed of the train without any stoppage and delay than stoppage and delay if the distance between Howrah and the source is 755km?
Time is taken by the Train to reach the destination at a speed of 55k/hr. = 755/55 = 13.72 hr.
If ignore the stoppage and delay time, then the total time taken = (13.72x 60)-(23x2)-30 min by Train to cover the distance = (823.63 -46-30) min
= 747.63 min or 12.46 hr.
New Average speed of the train = 755km ./12.46 hr. = 60.59km / hr
Percentage more than with delay and stoppage= ( 60.59-55)/55 = 0.1016 x 100 = 10.16%
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