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ATQ, Speed of the Cat = 54 × (5/18) = 15 m/s Distance covered by the dog in 6(2/3) seconds = 240 + distance covered by the cat in 6(2/3) seconds = 240 + 15 × (20/3) = 240 + 100 = 340 metres So, speed of the dog = 340 ÷ (20/3) = 51 m/s Relative speed of the dog with respect to the bus = 51 – 21 = 30 m/s Length of the bus = 21(2/3) × 21 = (65/3) × 21 = 455 metres So, time taken by the dog to overtake the bus = 455/30 = 91/6 seconds
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