Question
Three runners A, B and C run a race, with runner A
finishing 12 meters ahead of runner B and 18 meters ahead of runner C, in another race of same type runner B finished 8 meters ahead of runner C. Each runner travels the entire distance at a constant speed. the length of the race is.Solution
Let A finish the race of = x m B finish the race of =x-12 C finish the race of =x-18 … (1) In another race of B and C B finish race of =x C finish race of =x-8 … (2) Ratio of speeds of B and C (x-12)/(x-18) =x/x-8 (x-12) ×(x-8) =x(x-8) 2x=96 X=48meter.
If a = 2 + √3, then the value of (a6 + a4 + a2 + 1)/a3 is
If
= 4 then (p + q) = 8 and (p2 + q2 - 6) = 28. If p < q, then determine the value of (p/q).
If √m + (1/√m) = 7, then find the value of m + (1/m).
if a2 + b2 + c2 = 2(3a -5b -6c)-70 , then a-b-c = ?
√(92×8 ×52+700) = ?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
If p3 + 9p2 + 8p + 13 = 6p2 + 5p + 12, then find the value of {(p4 + 1/p2)}/(p2 + 3p +...
f(y) = y² – 5y + 6. Determine f(3) + f(–2).
If ( m+n ) : √ (mn) = 4, m>n , Then find the value of m : n ?
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