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ATQ, Let the total distance covered by ‘Axar’ be ‘4a’ km ATQ, (a/25) + {3a/(2 × 30)} + {3a/(2 × 25)} = 6 Or, 60a + 75a + 90a = 9000 Or, 4a + 5a + 6a = 600 Or, 15a = 600 Or, a = 600/15 = 40 Therefore, total distance covered by ‘Axar’ = 4x = 4 × 40 = 160 km
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