Question
A train would take 20 seconds to cross a stationary
pole. If the train was 200m shorter, it would have taken 10 seconds less. Find the speed of the train.Solution
Let the original length of the train = x m ∴ Speed of the original train = x/20 m/s ∴ Length of the shorter train = (x - 200) ∴ speed of the shorter train = (x - 200)/10 m/s Since, both the train are same their speed are also same. ∴ `(x)/20 = (x-200)/10` => 10x = 20x - 4000 => 10x = 4000 => x = 400 ∴ Speed = x/20 = 400/20 = 20m/s
Statements: A > E ≤ B; G < C ≤ E; D < C ≤ F
Conclusions:
I. D < B
II. F ≤ E
III. A > G
...Statements: M > Q ≥ U = O, S = U < R ≤ T
Conclusions :I. M < R II. T > O III. Q ≥ T
Statements: E < F > G; H < I ≤ F; E > D
Conclusions:
I. F > D
II. H < E
III. G < D
Statements: Q ≥ B > G = F ≥ J; W ≤ B = N < L.
Conclusions:
I. N > J
II. Q > L
In this question, the statement is followed by two conclusions. Which of the two conclusion(s) is/are true?
Statement: Z < L < P = V ≥ H = U �...
Statements: A % O & Z % O; O # C & E; E @ P # D
Conclusions : I. C @ P II. A % P ...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
Statements: W ≤ T = R; T < U < S; X = W ≥ Y
Conclusions:
I. S > Y
II. W ≥ S
III. U ≥ Y
Statements: E > G < H > F = I ≥ J > K ≥ D
Conclusion
I: J < H
II: I > D
Statements: U ≤ X = V < W; V > T = Q ≥ R
Conclusions: I. V ≥ R II. W > R
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