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Let the original length of the train = x m ∴ Speed of the original train = x/20 m/s ∴ Length of the shorter train = (x - 200) ∴ speed of the shorter train = (x - 200)/10 m/s Since, both the train are same their speed are also same. ∴ `(x)/20 = (x-200)/10` => 10x = 20x - 4000 => 10x = 4000 => x = 400 ∴ Speed = x/20 = 400/20 = 20m/s
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