Amit needs to travel a distance of 612 km. He covers a portion of the distance by scooty, with an average speed of 72 km/h, and the remaining distance by cycle, whose average speed is 25% less than that of the Scooty. If Amit takes 1.5 hours less than the time it takes to cover the entire distance only by Scooty, determine the distance covered by the cycle.
ATQ, Speed of cycle = 0.75 × 72 = 54 km/h Let, the distance covered by cycle be 'a' km. Since, the difference in time is only because of the distance which was covered by the cycle earlier is now covered by Scooty. [(612 - a) /54] - [(612 - a) /72] = 1.5 Or, [(612 - a) /18] × [(1/3) - (1/4) ] = 1.5 Or, [(612 - a) /18] × (1/12) = 1.5 Or, 612 - a = 1.5 × 18 × 12 Or, 612 - a = 324 Or, a = 612 - 324 So, a = 288 So, the distance covered by cycle = a = 288 km
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