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    Question

    A ship, labeled as Ship A, departs from Mumbai to Pune

    at 11:25 am, traveling at an average speed of 22.5 m/s. Simultaneously, Ship B travelled from Pune to Mumbai at 1:05 pm, maintaining an average speed of 17.5 m/s. Determine the time at which the two ships will meet, given that the distance between Mumbai and Pune is 615 km.
    A 12:00 pm Correct Answer Incorrect Answer
    B 3:25 pm Correct Answer Incorrect Answer
    C 4:25 pm Correct Answer Incorrect Answer
    D 6:25 pm Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Speed of Ship A = 22.5 × 18/5 = 81 Km/h Speed of Ship B = 17.5 × 18/5 = 63 Km/h Distance travelled by Ship A till 1:05 am = 81 × (5/3) = 135 Km Relative speed of shipes = 81 + 63 = 144 Km/h Remaining distance to be travelled after 1:05 pm = 615 - 135 = 480 Km Time taken to cover 480 Km = 480/144 = 10/3 = 3 hours 20 minutes So the two shipes will meet each other at 1:05 + 3:20 = 4:25 pm

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