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ATQ, Let the length of the bus be 'x' meters. So according to question: x/10 = (x + 405) /28 28x = 10x + 4050 18x = 4050, x = 225 So, the length of the bus = 225 meters Speed of the bus = 225/10 = 22.5 m/s Speed of the boy = 9 X 5/18 = 2.5 m/s Relative speed of the bus = 22.5 + 2.5 = 25 m/s So, the time taken by the bus to cross the boy = 225/25 = 9 seconds
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