ATQ, Let the length of the bus be 'x' meters. So according to question: x/10 = (x + 405) /28 28x = 10x + 4050 18x = 4050, x = 225 So, the length of the bus = 225 meters Speed of the bus = 225/10 = 22.5 m/s Speed of the boy = 9 X 5/18 = 2.5 m/s Relative speed of the bus = 22.5 + 2.5 = 25 m/s So, the time taken by the bus to cross the boy = 225/25 = 9 seconds
?% of 1200.22 + 319.82 = 3.99 × 295.64
12.99% of 499.99 ÷ 13.17 = ? ÷ 20.15
What will be the approximate value of the following questions.
(79.79% of 400.23 + 7/8 of 319.77) × (√35.66 + 1/5 of 200.27) = ?
30.22% of (61.9 × 5.01) + 69.97 =?
25.22 of 359.98% + 499.99 ÷ 25.18 = ?
(2310.23 ÷ 32.98) + (1008.32 ÷ 23.9) + 1594.11 = ?
1120.04 – 450.18 + 319.98 ÷ 8.06 = ?
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
5.25 x 4.09 + 3.99 x 9.67 + 6.01 x 14.88 = ?